(x^-3-x^-8)=(x^-2+x^-6)

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Solution for (x^-3-x^-8)=(x^-2+x^-6) equation: 



(x^-3-x^-8)=(x^-2+x^-6)

We move all terms to the left:

(x^-3-x^-8)-((x^-2+x^-6))=0

We get rid of parentheses

x^-x^-((x^-2+x^-6))-3-8=0



We calculate terms in parentheses: -((x^-2+x^-6)), so:

(x^-2+x^-6)

We get rid of parentheses

x^+x^-2-6

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

-(2x-8)-11=0

We get rid of parentheses

-2x+8-11=0

We add all the numbers together, and all the variables

-2x-3=0

We move all terms containing x to the left, all other terms to the right

-2x=3

x=3/-2

x=-1+1/2

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